0=p^2+11p-6

Solution for 0=p^2+11p-6 equation:

0=p^2+11p-6

We move all terms to the left:

0-(p^2+11p-6)=0

We add all the numbers together, and all the variables

-(p^2+11p-6)=0

We get rid of parentheses

-p^2-11p+6=0

We add all the numbers together, and all the variables

-1p^2-11p+6=0

a = -1; b = -11; c = +6;
Δ = b2-4ac
Δ = -112-4·(-1)·6
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{145}}{2*-1}=\frac{11-\sqrt{145}}{-2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{145}}{2*-1}=\frac{11+\sqrt{145}}{-2}
$